2) Add 1/3n + 2/3 and -1/6n + 1/6m

HELP PLEASE!! Which of the following best describes the graph below? A. it us a one-to-one function B. it us a function but it i

masha68 [24]

The correct statement regarding the function $y = \sqrt{x + 2}$ is given by:

A. it us a one-to-one function.

<h3>What is the missing information?</h3>

This problem is incomplete, but researching it on the internet, the function used is $y = \sqrt{x + 2}$ .

<h3>Is it a function?</h3>

For $y = \sqrt{x + 2}$ , each value of x is associated with only one value of y, that is, the graph has <u>no vertically aligned points</u>, hence it is a function.

<h3>Is the function one-to-one?</h3>

Each value of y is also associated with only one value of x, that is, the graph has <u>no horizontally aligned points</u>, hence it is a one-to-one function, and the correct statement is given by:

A. it us a one-to-one function.

More can be learned about functions at brainly.com/question/24808124

#SPJ1

8 0

2 years ago

At a Noodles & Company restaurant, the probability that a customer will order a nonalcoholic beverage is .51.

satela [25.4K]

Answer:

$P(x\geq 7)=0.1886$

Step-by-step explanation:

The variable x, that said the number of customer that will order a nonalcoholic beverage in a sample of n customers follows a binomial distribution. Because we have n identical and independent events with a probability p of success and (1-p) of fail.

So, the probability that x customers will order a nonalcoholic beverage is:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}$

Where n is the size of the sample and p is the probability that a customer order a nonalcoholic beverage, so replacing the values, we get:

$P(x)=\frac{10!}{x!(10-x)!}*0.51^{x}*(1-0.51)^{10-x}$

Now, the probability that at least 7 will order a nonalcoholic beverage is equal to:

$P(x\geq 7)=P(7)+P(8)+P(9)+P(10)$

Where:

$P(7)=\frac{10!}{7!(10-7)!}*0.51^{7}*(1-0.51)^{10-7}=0.1267\\P(8)=\frac{10!}{8!(10-8)!}*0.51^{8}*(1-0.51)^{10-8}=0.0494\\P(9)=\frac{10!}{9!(10-9)!}*0.51^{9}*(1-0.51)^{10-9}=0.0114\\P(10)=\frac{10!}{10!(10-10)!}*0.51^{10}*(1-0.51)^{10-10}=0.0011$

So, $P(x\geq 7)$ is equal to:

$P(x\geq 7)=0.1267+0.0494+0.0114+0.0011\\P(x\geq 7)=0.1886$

Finally, the probability that in a sample of 10 customers, at least 7 will order a nonalcoholic beverage is equal to 0.1886

5 0

3 years ago

When Mei does 17 push-ups and 6 sit-ups, it takes a total of 35 seconds. In comparison, she needs 41 seconds to do 20 push-ups a

Romashka [77]

Answer:

It takes 1 seconds for push-ups and 3 seconds for sit-ups for Mei to do exercise.

Step-by-step explanation:

Given:

Let the time taken for push-ups be 'x'.

Let the time taken for sit-ups be 'y'.

Now Given:

17 push-ups and 6 sit-ups, it takes a total of 35 seconds.

So we can say that;

$17x+6y=35 \ \ \ \ equation \ 1$

Also Given:

41 seconds to do 20 push-ups and 7 sit-ups.

so we can say that;

$20x+7y=41 \ \ \ \ equation \ 2$

Now Multiplying equation 1 by 7 we get;

$7(17x+6y)=35\times7\\\\119x+42y= 245 \ \ \ \ equation \ 3$

Now Multiplying equation 2 by 6 we get;

$6(20x+7y)=41\times6\\\\120x+42y = 246 \ \ \ \ equation\ 4$

Now Subtracting equation 3 from equation 4 we get;

$120x+42y-(119x+42y)=246-245\\\\120x+42y-119x-42y=1\\\\x=1\ sec$

Now substituting the value of x in equation 1 we get;

$17x+6y=35\\\\17\times1+6y=35\\\\17+6y=35\\\\6y=35-17\\\\6y= 18\\\\y=\frac{18}6 = 3\ seconds$

Hence It takes 1 seconds for push-ups and 3 seconds for sit-ups for Mei to do exercise.

7 0

3 years ago

67. The line contains the point (4,0) and is parallel<br> to the line defined by 3x = 2y.

olganol [36]

Answer:

$y=\frac{3}{2} x-6$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form:

$y=mx+b$ where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)

Parallel lines will always have the same slope but different y-intercepts.

<u>1) Determine the slope of the parallel line</u>

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

$3x = 2y$

Switch the sides

$2y=3x$

Divide both sides by 2 to isolate y

$\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x$

Now that this equation is in slope-intercept form, we can easily identify that $\frac{3}{2}$ is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope $\frac{3}{2}$ . Plug this into $y=mx+b$ :