I hope this helps you
length =width +6
Area=width × length
Area=w. (w+6)
Answer: Its A.) 10y
Step-by-step explanation:
The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
Answer:
The actual building will be 7.5 m tall
Step-by-step explanation:
Given the scale model value of the building, we want to find the actual height of the building
From the scale model;
1 cm = 0.5m
Thus 15 cm will be 15 * 0.5 = 7.5 m
Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
x = [-5 ± √(25 - (104) ) ] / ( -4 )
x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
