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3 years ago

What is the area, in square centimeters, of the figure below? *

Mathematics

1 answer:

salantis [7]3 years ago

6 0

Answer:

Hello I believe the answer is 6.96 But I dont know for sure so answer that at your OWN risk.

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The stemplot displays the selling prices of homes for ABC Realty in April.

Alexxandr [17]

The stemplot displays the entire values for the selling prices of homes for ABC Reality in April.

The correct set of data for the stemplot is the option;

$459,000, $227,000, $67,000, $123,000, $213,000, $482,000, $85,000, $181,000, $225,000, $92,000, $181,000, $287,000, $196,000, $276,000

<h3>Method by which the above option is selected</h3>

The data in the stemplot are;

459,000, 482,000, 213,000, 225,000, 276,000, 277,000, 287,000, 123,000, 181,000, 181,000, 196,000, 67,000, 85,000, 92,000

Given that there are no values in the 300,000s, and that 181,000 appear twice, the option that corresponds to the above data is therefore;

$459,000, $277,000, $67,000, $123,000, $213,000, $482,000, $85,000, $181,000, $225,000, $92,000, $181,000, $287,000, $196,000, $276,000

Learn more about stemplot here:

brainly.com/question/10572086

6 0

2 years ago

Find the GCF of the terms of the polynomial. 30x3 + 16x5 a. x3 b. 2x3 c. 2x5 d. 16x

Vladimir79 [104]

You can take out 2x^3 from both terms making it
2x^3 (15+8x^2)
Answer is B

3 0

3 years ago

Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables X and Y is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0

3 years ago

Thanks, & yes how did you get that

soldier1979 [14.2K]

Hello Vmcdowell43

The word Thanks is a shorter way of saying Thank you. Many people use it because it is easier.

The word yes is a simple way to agree with something.

Hope that helps!
-Chris

6 0

3 years ago

What can be measured by meters

shusha [124]

Meters are used to measure everything between the length of a ruler and the distance between things in a room. Most household objects such as tables, rooms, window frames, television screens, etc. would be measured in meters. Kilometers are used to measure long distances.

4 0

3 years ago