Answer:
<em>yes</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>angle</em><em> </em>
<u>w</u><u>=</u><u>-</u><u>1</u><u>.</u><u>5</u>
<u>w</u><u>=</u><u>2</u>
Answer:
Solution given:

again
keep square root alone

solve subtraction of 7-2

Squaring on both side

2w²-19w+31=5²-2*5*2w+4w²
take terms one side
2w²-19w+31-25+20w-4w²=0
-2w²+w+6=0
2w²-w-6=0
doing middle term factorisation
2w²-(4-3)w-6=0
2w²-4w+3w-6=0
take common from each two term
2w(w-2)+3(w-2)=0
(w-2)(2w+3)=0
either
w=2
or
W=-3/2=-1.5
Answer:
<h2>first blank:</h2><h2>c=sqrt(a^2+b^2)</h2><h2>second blank:</h2><h2>c=sqrt((8-2)^2+(-5-3)^2)</h2><h2 />
Step-by-step explanation:
c^2=a^2+b^2
sqrt(c^2)=sqrt(a^2+b^2)
c=sqrt(a^2+b^2)
c=sqrt((x2-x1)^2+(y2-y1)^2)
c=sqrt((8-2)^2+(-5-3)^2)
I am pretty sure the answer for the first one is x=-.498
Answer:
x = -8
Step-by-step explanation: