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Blizzard [7]
3 years ago
6

At a snack stand, hot dogs cost $3.50 and hamburgers cost $5. If the snack stand sold 27 snacks and made $118.50 in revenue, how

many hot dogs were sold? How many hamburgers?
Mathematics
1 answer:
ra1l [238]3 years ago
3 0

Answer:the number of hot dogs that were sold is 11

the number of hamburgers that were sold is 16

Step-by-step explanation:

Let x represent the number of hot dogs that were sold.

Let y represent the number of hamburgers that were sold.

At a snack stand, hot dogs cost $3.50 and hamburgers cost $5. If the snack stand sold 27 snacks and made $118.50 in revenue, this means that

x + y = 27 - - - - - - - - - -1

3.5x + 5y = 118.5 - - - - - - - 2

Substituting x = 27 - y into equation 2, it becomes

3.5(27 - y) + 5y = 118.5

94.5 - 3.5y + 5y = 118.5

- 3.5y + 5y = 118.5 - 94.5

1.5y = 24

y = 24/1.5 = 16

x = 27 - y = 27 - 16 = 11

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Answer:

-2

Step-by-step explanation:

7−5+3−1  

using BODMAS

A is addition and it comes before subtraction

7−(5+3)−1

7-8-1

then solve

7 - 9 = -2

4 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △LMN that is parallel to LN¯¯¯¯¯ ?
Brut [27]
<span>(3, 4.5) and (3, 3)

       The midsegment of a triangle is a line connecting the midpoints of two sides of the triangle. So a triangle has 3 midsegments. Since you want the midsegment that's parallel to LN, we need to select the midpoints of LM and MN. The midpoint of a line segment is simply the average of the coordinates of each end point of the line segment. So:

   Midpoint LM:

   ((0+6)/2, (5+4)/2) = (6/2, 9/2) = (3, 4.5)

       Midpoint MN:

   ((6+0)/2, (4+2)/2) = (6/2, 6/2) = (3, 3)

       So the desired end points are (3, 4.5) and (3, 3)</span>
3 0
3 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
2 years ago
A rectangular site measures 125 feet (frontage) by 256 feet (depth), of which 26 feet is in the public right of way. what is the
alexandr1967 [171]

Answer:

32,000 square feet gross area and 28,750 square feet net area

Step-by-step explanation:

Given a rectangular site measures 125 feet (frontage) by 256 feet (depth), of which 26 feet is in the public right of way. We have to find the  the gross and net site area.

As, 26 feet width is in the public right of way which excluded in the net area but included in gross area.

For gross area,

Length=125 feet

Width=256 feet

Area=Length\times width=125\times 256=32000 square feet

For net area,

Length=125 feet

Width=256-26=230 feet

Area=Length\times width=125\times 230=28750 square feet

Hence, last option is correct.

The answer is:  32,000 square feet gross area and 28,750 square feet net area

6 0
3 years ago
a park covers a total area of 644 acres there are 482 more acres of woods than grassy areas in the park how many acres are there
maw [93]

Answer:

woods are 81 acres, grass 563 acres

Step-by-step explanation:


3 0
3 years ago
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