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Allisa [31]
3 years ago
15

What is it multiplying by?784.5, 78.45, 7.845,0.7845, 0.07845

Mathematics
1 answer:
katrin [286]3 years ago
3 0

Answer:

10,100,1000,-10,-100,-1000

Step-by-step explanation:

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It is 7. None of the other ones fit at all
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A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple
tester [92]

Answer:  The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation:  We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.

Therefore, the probability of event A is given by

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0
3 years ago
At the local grocery store, cans of beans are arranged in rows. The number of cans in each row forms an arithmetic sequence. The
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In an arithmetic series, the value of the nth term is calculated using the equation,
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In the given, an = 48, a0 = 93, d = -5 and n is unknown. Substituting the known values,
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3 years ago
Complete the square to the problem X^2+6x-16=0
marishachu [46]

Answer:

<h2>x = -8 or x = 2</h2>

Step-by-step explanation:

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3 years ago
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IgorC [24]
1/25 or .04% would be the correct answer

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