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2 years ago

Which relation is a function of x?

Mathematics

2 answers:

Orlov [11]2 years ago

8 0

The function of the relation is: x3

Hope this helps you!! :)

stiv31 [10]2 years ago

7 0

Answer:

Step-by-step explanation:

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Write the ratios for Sin A Cos A, and Tan A.

Nataliya [291]

Step-by-step explanation:

sinA= BC/AC

= 24/26

= 12/13

cosA= AC/AB

= 10/26

= 5/13

tanA= BC/AC

=24/10

= 12/5

4 0

2 years ago

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Suppose cos(x)= -1/3, where π/2 ≤ x ≤ π. What is the value of tan(2x). EDGE

AVprozaik [17]

Answer:

Step-by-step explanation:

We are given that:

$\displaystyle \cos x = -\frac{1}{3}\text{ where } \pi /2 \leq x \leq \pi$

And we want to find the value of tan(2<em>x</em>).

Note that since <em>x</em> is between π/2 and π, it is in QII.

In QII, cosine and tangent are negative and only sine is positive.

We can rewrite our expression as:

$\displaystyle \tan(2x)=\frac{\sin(2x)}{\cos(2x)}$

Using double angle identities:

$\displaystyle \tan(2x)=\frac{2\sin x\cos x}{\cos^2 x-\sin^2 x}$

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

$\displaystyle o=\sqrt{3^2-1^2}=\sqrt{8}=2\sqrt{2}$

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.

From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence:

<h2> $\displaystyle \tan(2x)=\frac{2(2\sqrt{2}/3)(-1/3)}{(-1/3)^2-(2\sqrt{2}/3)^2}$ </h2>

Simplify:

$\displaystyle \tan(2x)=\frac{-4\sqrt{2}/9}{(1/9)-(8/9)}$

Evaluate:

$\displaystyle \tan(2x)=\frac{-4\sqrt{2}/9}{-7/9} = \frac{4\sqrt{2}}{7}$

The final answer is positive, so we can eliminate A and B.

We can simplify D to:

$\displaystyle \frac{2\sqrt{8}}{7}=\frac{2(2\sqrt{2}}{7}=\frac{4\sqrt{2}}{7}$

So, our answer is D.

7 0

3 years ago

Dante bought a new graduated cylinder for his chemistry class. It holds 1,345.6 milliliters of liquid. If the cylinder has a rad

pentagon [3]

The formula for a cylinder's volume is
V = π r² h
V = 1345.6
π = 3.14
r = 5.8 cm

1345.6 = 3.14 * 5.8^2 h Multiply 3.14 and 5.8^2 together.
1345.6 = 105.6 h Divide by 105.6
1345.6 / 105.6 = h
h = 12.73 cm <<<< answer.
I don't see anything wrong with what I've done but I don't see the answer anywhere. Estimating 1345 can be rounded to 1300.
pi * 5.8^2 = 3 * 35 = 105 which we could round to 100.

1300 / 100 about = 13 So the answer should be in the region of 100.

I cannot see any reason to believe there is an error. If there is something that has not been copied correctly, I'd like to know what it is.

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2 years ago

Can someone help me with this? i'll award brainiest :D

Burka [1]

Answer:

About 79 boys i think

Step-by-step explanation:

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2 years ago

If the perimeter of an isosceles triangle is

ankoles [38]

Answer:

6 cm for both sides

Step-by-step explanation:

5 0

2 years ago

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