Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
Answer:
The equation is wrong
Step-by-step explanation:
if you read the description closley, it matches eith rhe table and the graph but if you know how to do the equation, its no -5/2x+40
Answer:
MAYBE: 14?
Step-by-step explanation:
i just read it in the pic above and worked it out.
