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weeeeeb [17]
3 years ago
13

Latasha played a game where she could either lose or gain points each round. at the end of 8 rounds , she has 19 points . After

one more round,she had 7 points . Express the change in on points in the most recent round as a integer Heeeeeeeellllllllllllpppppppppp nfffffffffaaaaaaaaasssssssssstttttttttttttttttt
Mathematics
2 answers:
zmey [24]3 years ago
8 0

Answer:

the answer is  26

Step-by-step explanation:

snow_lady [41]3 years ago
5 0

Answer:

what are you telling I didn't know

You might be interested in
PLEASE HELP ILL GIVE BRAINLIESTTTT
Yakvenalex [24]

Answer:

f(-3) = -2

f( 1 ) = - 1

If f(x) = -2, then x = 3

If f(x) = 2, then x = -5

Step-by-step explanation:

Looking at the graph, we can easily determine the value of the given functions.

f(-3) = -2 (This function basically asks, if x = -3, what is the value of y? In the graph, it shows that the value of y is -2).

f( 1 ) = - 1  (Similarly, this function  asks, if x = 1, what is the value of y? In the graph, it shows that the value of y is -1).

If f(x) = -2, then x = ?  ←← For this particular question, you're given the value of y = -2. All you need to do is look at the graph to see what is the value of x  given that y = -2. Even though it is not clearly labeled on the graph, it shows the value of x = 3 (it is right where the end arrow is located).

Therefore, If f(x) = -2, then x = 3.

If f(x) = 2, then x = ?  ←← Similar to the previous question, you're given the value of y = 2.  In the graph, one of the given points has the coordinates of (-5, 2). This gives you the value of x = -5.

Therefore, If f(x) = 2, then x = -5.

Please mark my answers as the Brainliest if you find my explanations helpful :)

3 0
2 years ago
Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
2 years ago
I will mark as brilliant please help
vodomira [7]
It’s C. x_< -2 Good luck
8 0
3 years ago
Please help guys -_-
baherus [9]

Answer:

C. the remainder must always be less than the dividend

5 0
3 years ago
Read 2 more answers
8th grade math help please (will give brainliest and thanks)
kari74 [83]
Pythagorean Theorem
Height = 3
Length = 5
Hypotenuse^2 = 3^3 + 5^2
Hypotenuse^2 = 9 + 25
Hypotenuse^2 = 34
Line CD = sq root(34) = <span> <span> <span> 5.8309518948 </span> </span> </span>

7 0
3 years ago
Read 2 more answers
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