Answer:
6.0 moles of H₂S are produced.
Explanation:
Let's consider the following balanced equation.
2 CH₄ + S₈ → 2 CS₂ + 4 H₂S
The molar ratio of S₈ to H₂S is 1 mol S₈: 4 mol H₂S. The moles of H₂S produced when 1.5 mol of S₈ react are:
1.5 mol S₈ × (4 mol H₂S/ 1 mol S₈) = 6.0 mol H₂S
6.0 moles of H₂S are produced, when 1.5 mol of S₈ react.
1) Reactions which<span> involves both a </span>reduction<span> process and a complementary </span>oxidation<span> process are called </span>oxidation-reduction.they <span>can't be double replacement reactions.</span>
Hence,
WO3 + 3H2 ---> W + 3H2O is an oxidation-reduction reaction