Answer:
A monosaccharide that contains 4 carbon atoms, one of which is in an aldehyde group, is classified as an aldotetrose.
Explanation:
A tetrose is a monosaccharide with 4 carbon atoms.
They have either an aldehyde functional group in position 1 (aldotetroses).
or a ketone functional group in position 2 (ketotetroses).
So, A monosaccharide that contains 4 carbon atoms, one of which is in an aldehyde group, is classified as an aldotetrose.
Answer:
The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³
Explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.
pOH indicates the concentration of hydroxyl ions [OH-] present in a solution. In this way, pOH is defined as the negative logarithm of the activity of hydroxide ions, that is, the concentration of OH- ions:
pOH= -log [OH⁻]
In this case, pOH has a value of 2.7. Replacing:
2.7= -log [OH⁻]
and solving:
[OH⁻]=10⁻² ⁷
you get:
[OH⁻]≅ 2*10⁻³
<u><em>The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³</em></u>
