So subsitue and try so
f(g(x))=2(7x+1)+2
g(f(x))=7(2x+2)+1
multiply them out
f(g(x))=2(7x+1)+2=14x+2+2=14x+4
g(f(x))=7(2x+2)+1=14x+14+1=14x+15
14x+15>14x+4
therefor
g(f(x))>f(g(x))
the answer is D g(f(x)) produces the greatest output
The answer is Difference of Cubes.
Difference of cubes is a³ - b³.
27 can be written as 3³ (= 3 × 3 × 3 = 27). So, a = 3.
8 can be written as 2³ (= 2 × 2 × 2 = 8). So, b = 2.
Difference of cubes can be expressed as:
a³ - b³ = (a - b)(a² + ab + b²)
⇒ 3³ - 2³ = (3 - 2)(3² + 3×2 + 2²) = 1 × (9 + 6 + 4) = 1 × 19 = 19
⇒ 27 - 8 = 19
Step-by-step explanation:
hope it helps you..........
Answer:
- 30/91
Step-by-step explanation:
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