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3 years ago

What is the slope of the line represented by the equation y=2

1 answer:

6 0

Remember y=mx+b

Since y=2 that means it is a horizontal line at 2 on the y axis which means it does not have a slope. The slope would be zero.

You might be interested in

Find the measure of <4. { 44 158° { 44 = [?]

VLD [36.1K]

Answer:

<4 = 22

Step-by-step explanation:

<4 = x

x + 158 = 180

x = 22

4 0

2 years ago

Juan and Franco collect baseball cards. Juan has baseball cards. Franco has 18 fewer baseball cards than Juan. Together they hav

horsena [70]

Answer:

Franco has 66 baseball cards.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of baseball cards that Franco has.

y is the number of baseball cards that Juan has.

Franco has 18 fewer baseball cards than Juan.

This means that:

$x = y - 18$

Also:

$y = x + 18$

Together they have 150 baseball cards.

This means that:

$x + y = 150$

Since $y = x + 18$

$x + x + 18 = 150$

$2x = 132$

$x = \frac{132}{2}$

$x = 66$

Franco has 66 baseball cards.

8 0

3 years ago

What is the approximate volume of a cylinder with a diameter of 10 meters and a height of 5 meters? Use 3.14 for pi. A. 392.5 m3

EastWind [94]

For cylinder
d=10m
So r=5m
h=5m
volume=pi×r^2×h
=3.14×5×5×5
=3.14×125
=392.5m^3
So option a is correct.

3 0

3 years ago

Read 2 more answers

Find the mode: 5, 0, 9, 9, 3, 0, 5, 5, 4

Fed [463]

Answer:

Step-by-step explanation:

Occurs most often

5 0

3 years ago

The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate

Schach [20]

Answer:

(a)0.16

(b)0.588

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

$\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix $P^k$ .

(a)

$P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

$P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}$

If the system is initially running, the probability of the system being down in the next hour of operation is the $(a_{12})th$ entry of the P^2$ matrix.$

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

$P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}$

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, $S=[s_1$ s_2]$

$[s_1$ s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$ s_2]$

Using a calculator to raise matrix P to large numbers, we find that the value of $P^k$ approaches [0.75 0.25]:

Furthermore,

$[0.75$ 0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$ 0.25]$

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

$[s_1$ s_2]=[0.75$ 0.25]$

4 0

3 years ago