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mars1129 [50]
3 years ago
10

What is the missing value x/24 + 35/60

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
5 0

Answer:

14

Step-by-step explanation:

x/24=35/60

x=(24*35)/60

x=14

Hope this helps plz hit the crown :D

Second way:

35/60 divided by 5

7/12

x/24=7/12

1/2x/12 = 7/12

1/2x=7

x=14

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if I went to store with 90.00 and spent 36.81 and got 20% off what would I have left need answer fast thanks
vichka [17]
I'm guessing the 20 percent off is from the $36.81 so you take 36.81 times 0.80 making it $29.448. Take 90 dollars and minus that amount.

Answer: $60.552 
Rounded Answer: $60.55 or $60.60 or $61

Not sure if this helped, but yeah.....
3 0
3 years ago
What's the answer?????????????
Taya2010 [7]

Answer:

BD = 12 :)

Step-by-step explanation:

Alright, we'll need the Pythagorean theorem for this!

So, the length of AC is 10. That means the lengths of AD and DC are both half of that, which is 5 :)

DC = 5

We already know that BC = 13, so we can plug in these values into the pythagorean theorem for the right triangle BDC:

BD^2 + DC^2 = BC^2

BD^2 + 5^2 = 13^2

BD^2 + 25 = 169

BD^2 = 169 - 25 = 144

BD = √144 = 12 :)

3 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Ne4ueva [31]

Answer:

Part 1) -1.25 -------> 2.75/(-2.2)

Part 2) -4\frac{1}{3} --------> (-2\frac{3}{5}) / (\frac{3}{5})

Part 3) \frac{2}{3} ------> (-\frac{10}{17}) / (-\frac{15}{17})

Part 4) 3 ------> (2\frac{1}{4}) / (\frac{3}{4})

Step-by-step explanation:

Part 1) we have

2.75/(-2.2)

To calculate the division problem convert the decimal number to fraction number

2.75=275/100\\ -2.2=-22/10      

so

(275/100)/(-22/10)

Remember that

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

(275/100)/(-22/10)=(275/100)*(-10/22)=-(275*10)/(22*100)=-(275)/(220)

Simplify

Divide by 22 both numerator and denominator

-(275)/(220)=-125/100=-1.25

Part 2) we have

(-2\frac{3}{5}) / (\frac{3}{5})

To calculate the division problem convert the mixed number to an improper fraction  

(-2\frac{3}{5})=-\frac{2*5+3}{5}=-\frac{13}{5}

so

(-\frac{13}{5}) / (\frac{3}{5})

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

(-\frac{13}{5}) / (\frac{3}{5})=(-\frac{13}{5})*(\frac{5}{3})=-\frac{13*5}{5*3}=-\frac{13}{3}

Convert to mixed number

-\frac{13}{3}=-(\frac{12}{3}+\frac{1}{3})=-4\frac{1}{3}

Part 3) we have

(-\frac{10}{17}) / (-\frac{15}{17})

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

(-\frac{10}{17}) / (-\frac{15}{17})=(-\frac{10}{17})*(-\frac{17}{15})=\frac{10*17}{17*15}=\frac{10}{15}

Simplify

Divide by 5 both numerator and denominator

\frac{10}{15}=\frac{2}{3}

Part 4) we have

(2\frac{1}{4}) / (\frac{3}{4})

To calculate the division problem convert the mixed number to an improper fraction  

(2\frac{1}{4})=\frac{2*4+1}{4}=\frac{9}{4}

so

(\frac{9}{4}) / (\frac{3}{4})

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

(\frac{9}{4}) / (\frac{3}{4})=(\frac{9}{4})*(\frac{4}{3})=\frac{9*4}{4*3}=\frac{9}{3}=3

8 0
3 years ago
Classify the following triangle based on its angle measures.
gavmur [86]

Answer:

D.) Right

Explanation:

A.) An obtuse triangle is where one of the internal angles is obtuse (greater than 90 degrees).

B.) An acute triangle is a triangle with three acute angles (less than 90°).

C.) A right triangle is where one of its interior angles is a right angle (90 degrees).

D.) An equiangular triangle is a triangle where all three interior angles are equal in measure.

4 0
3 years ago
Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$
Viktor [21]

When n=0, we have

5^{3^0} + 1 = 5^1 + 1 = 6

3^{0 + 1} = 3^1 = 3

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for n=k, that

3^{k + 1} \mid 5^{3^k} + 1

Now for n=k+1, we have

5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)

so we know the left side is at least divisible by 3^{k+1} by our assumption.

It remains to show that

3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1

which is easily done with Fermat's little theorem. It says

a^p \equiv a \pmod p

where p is prime and a is any integer. Then for any positive integer x,

5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3

Furthermore,

5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3

which goes all the way down to

5^{3^k} \equiv 5 \pmod 3

So, we find that

\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3

QED

5 0
2 years ago
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