We can't write the product because there is no common input in the tables of g(x) and f(x).
<h3>Why you cannot find the product between the two functions?</h3>
If two functions f(x) and g(x) are known, then the product between the functions is straightforward.
g(x)*f(x)
Now, if we only have some coordinate pairs belonging to the function, we only can write the product if we have two coordinate pairs with the same input.
For example, if we know that (a, b) belongs to f(x) and (a, c) belongs to g(x), then we can get the product evaluated in a as:
(g*f)(a) = f(a)*g(a) = b*c
Particularly, in this case, we can see that there is no common input in the two tables, then we can't write the product of the two functions.
If you want to learn more about product between functions:
brainly.com/question/4854699
#SPJ1
I’m not sure what you’re options are but an equation in Y=mx+b form for this would be y= -3/2x + 5
M is always the slope
B is always the y intercept
Ion know about this I don’t know the answer fasho
Step 1
Collinear points are a set of three or more points that exist on the same straight line. Collinear points may exist on different planes but not on different lines.
Step 2
Graph the points; (-5,2),(0,6),(6,4)
Step 3
Conclude based on step 2
Since the points are not a straight line, we can conclude that the 3 points are not collinear.
Answer:
22 people
Step-by-step explanation:
Sean has 2 3/4 candy bars. That is 11/4 candy bars.
He wants to give out 1/8 candy bars.
The number of people that will get candy is:
![\frac{11}{4} / \frac{1}{8}\\ \\= \frac{\frac{11}{4} }{\frac{1}{8}} \\\\\frac{11}{4} * \frac{8}{1} \\\\22](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B4%7D%20%2F%20%5Cfrac%7B1%7D%7B8%7D%5C%5C%20%5C%5C%3D%20%5Cfrac%7B%5Cfrac%7B11%7D%7B4%7D%20%7D%7B%5Cfrac%7B1%7D%7B8%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B11%7D%7B4%7D%20%2A%20%5Cfrac%7B8%7D%7B1%7D%20%5C%5C%5C%5C22)
22 people can get candy.