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Maurinko [17]
3 years ago
6

Question 1

Mathematics
1 answer:
erica [24]3 years ago
6 0
Mean 22.71. Mode-None Median-30 Range-35
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HELP!!!!!!!!!!!!!!!!!!!!!!
Furkat [3]

Answer:

See below.

Step-by-step explanation:

Congruent sides:

SU and FO

UN and OG

SN and FG

Congruent angles:

<S and <F

<U and <O

<N and <G

6 0
3 years ago
Cho tam giác ABC có diện tích= 105cm vuông. Trung tuyến AM và BN cắt nhau tại G.
joja [24]

Answer:

english pls.

Step-by-step explanation:

showing wrong transalation in transalate

5 0
2 years ago
Triangle ABC is similar to triangle QRS by the AA Similarity Postulate. Also, m∠A = 32° and m∠S = 102°. What is m∠B?
nignag [31]
The sum of interior angles of any polygon is:

s=180(n-2)

Since we are dealing with a triangle:

s=180(3-2)

s=180°

That is, the sum of angles of any triangle is 180°.

In this case we are given two angles with measures of 32° and 102° so

a+b+c=180

32+b+102=180 combine like terms on left

b+134=180  subtract 134 from both sides

b=46°
5 0
3 years ago
Nina's net income was $423.65,and her gross income was $558.What was the total amount of deductions?
kompoz [17]
Gross=amount earned not minusing tax
net=amount earned minus tax

gross=558
net=423.65

deduction=gross-net
deduction=558-423.65=134.35

deduction=$134.35
4 0
3 years ago
A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

A=\pi r^{2}

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

6 0
4 years ago
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