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enot [183]
4 years ago
6

You are planning a picnic today, but the morning is cloudy Oh no! 50% of all rainy days start off cloudy! But cloudy mornings ar

e common (about 40% of days start cloudy) And this is usually a dry month (only 3 of 30 days tend to be rainy, or 10%) What is the chance of rain during the day?
Mathematics
1 answer:
Leviafan [203]4 years ago
5 0

Answer:

The chance of rain during the day is 1/10

Step-by-step explanation:

Probability is given by number of possible outcomes ÷ number of total outcomes = 3/30 = 1/10

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Stephanie has $152 in the bank. She withdraws $20 Then she deposits $84 Write an addition expression to represent this stiuation
tresset_1 [31]

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152-20+84= 216

Step-by-step explanation:

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Step-by-step explanation:

Angle 3 and angle 5 are on the same side of the transversal. Therefore,

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3 years ago
A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six
Zarrin [17]

Answer:

The volume of the box is maximized when x = 0.53 cm

Therefore,  x = 0.53 cm  and the Maximum volume = 1.75 cm³

Step-by-step explanation:

Please refer to the attached diagram:

The volume of the box is given by

V = Length \times Width \times Height \\\\

Let x denotes the length of the sides of the square as shown in the diagram.

The width of shaded region is given by

Width = 3 - 2x \\\\

The length of shaded region is given by

Length = \frac{1}{2} (5 - 3x) \\\\

So, the volume of the box becomes,

V =  \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V =  \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V =  \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V =  \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\

Take the derivative of volume and set it to zero.

\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15)\\\\18x^2 -38x + 15 = 0\\\\

We may solve the quadratic equation using the quadratic formula.

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

The values of coefficients a, b, c are

a = 18 \\\\b = -38 \\\\c = 15 \\\\

Substituting the values into quadratic formula yields,

x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 +  19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\

Volume of box when x = 1.59:

V =  \frac{1}{2} (5 - 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\

Volume of box when x = 0.53:

V =  \frac{1}{2} (5 - 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3

As you can see, the volume of the box is maximized when x = 0.53 cm

Therefore,  x = 0.53 cm  and the Maximum volume = 1.75 cm³

8 0
3 years ago
-13 > x -43 solve the inequality and enter your solution as inequality comparing the variable to the solution
ipn [44]

Answer:

30 > x

Step-by-step explanation:

-13 > x-43

-13 + 43 > x -43 + 43

30 > x

3 0
3 years ago
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