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enot [183]
4 years ago
6

You are planning a picnic today, but the morning is cloudy Oh no! 50% of all rainy days start off cloudy! But cloudy mornings ar

e common (about 40% of days start cloudy) And this is usually a dry month (only 3 of 30 days tend to be rainy, or 10%) What is the chance of rain during the day?
Mathematics
1 answer:
Leviafan [203]4 years ago
5 0

Answer:

The chance of rain during the day is 1/10

Step-by-step explanation:

Probability is given by number of possible outcomes ÷ number of total outcomes = 3/30 = 1/10

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-8(n - 2)= -2(4n - 5)+6
mixas84 [53]
All real number (any value of n makes the equation true)
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4 years ago
OK I NEED HELP I DONT KNOW THIS​
DiKsa [7]

Answer: what the question based on?

Step-by-step explanation:

4 0
2 years ago
Number 2 is the problem i need help with
Reptile [31]

Answer:

2a) $180

2b) $1440

Step-by-step explanation:

2a) Basically Samuel works for 6 hours a day and earns 7.50 per hour, so you have to do 7.50 x 6 to see how much he earns per day (which in this case is $45). You then have to multiply $45 to 4 since he earns $45 per day and works 4 days per week (which is $180).

2b) After finding out how much he earns per week ($180 from the previous question), you then have to multiply $180 by 8 as $180 is the amount he earns per week and since he works for 8 weeks you have to multiply $180 by 8 (the answer is then $1440).

sorry if I'm not making sense, i tried :) good luck!

8 0
3 years ago
Read 2 more answers
I need help plz will give brainliest!!!
Leokris [45]

Answer:

18 red marbles

Step-by-step explanation:

Because the ratio of yellow marbles to red marbles is 1:6 in the population, the expected number of red marbles is 6 times the number of yellow marbles in the representative sample. there should be 18 red marbles.

7 0
3 years ago
A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

C = Children; S = Students; A = Adults

For the capacity, we have:

C + S + A = 329

For the tickets sold, we have:

5C + 7S + 12A = 2388

Half as many as adults are children implies that:

A = \frac{C}{2}

Required

Solve for A, C and S

The equations to solve are:

C + S + A = 329 -- (1)

5C + 7S + 12A = 2388 -- (2)

A = \frac{C}{2} -- (3)

Make C the subject in (3)

C = 2A

Substitute C = 2A in (1) and (2)

C + S + A = 329 -- (1)

2A + S + A = 329

3A + S = 329

Make S the subject

S = 329 - 3A

5C + 7S + 12A = 2388 -- (2)

5*2A + 7S + 12A = 2388

10A + 7S + 12A = 2388

7S + 22A = 2388

Substitute S = 329 - 3A

7(329 - 3A) + 22A = 2388

2303 - 21A + 22A = 2388

2303 +A = 2388

Solve for A

A = 2388 - 2303

A = 85

Recall that: C = 2A

C = 2 * 85

C = 170

Recall that: S = 329 - 3A

S = 329 - 3 * 85

S = 329 - 255

S = 74

Hence, the result is:

C = 170

S = 74

A = 85

8 0
3 years ago
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