3 years ago

Four streets feed into a roundabout circle as shown below. If the diameter of the

Mathematics

1 answer:

Natasha2012 [34]3 years ago

5 0

Answer: 119.1ft............

You might be interested in

What is the ratio 5 to 105 expressed as a fraction in simplest form?

EastWind [94]

You start 5/105
Divide the numerator and denominator both by five to get 1/21

3 0

3 years ago

Can I get some help please?

sergij07 [2.7K]

The answer is the furthest to the right.

5 0

4 years ago

The population of a local species of bees can be found using an infinite geometric series where a1=860 and the common ratio is 1

erma4kov [3.2K]

$a_1=860$
$a_2=\dfrac{a_1}5$
$a_3=\dfrac{a_2}5=\dfrac{a_1}{5^2}$
$\vdots$
$a_n=\dfrac{a_{n-1}}5=\dfrac{a_{n-2}}{5^2}=\cdots=\dfrac{a_1}{5^{n-1}}$

The $k$ th partial sum is

$\displaystyle S_k=\sum_{n=1}^ka_n=\sum_{n=1}^k\frac{a_1}{5^{n-1}}$
$S_k=a_1\left(1+\dfrac15+\dfrac1{5^2}+\cdots+\dfrac1{5^{k-2}}+\dfrac1{5^{k-1}}$
$\dfrac15S_k=a_1\left(\dfrac15+\dfrac1{5^2}+\dfrac1{5^3}+\cdots+\dfrac1{5^{k-1}}+\dfrac1{5^k}\right)$

$\implies S_k-\dfrac15S_k=a_1\left(1-\dfrac1{5^k}\right)$
$\dfrac45 S_k=860\left(1-\dfrac1{5^k}\right)$
$S_k=1075-\dfrac{1075}{5^k}$

As $k\to\infty$ , we're left with

$\displaystyle\sum_{n=1}^\infty a_n=\lim_{k\to\infty}\left(1075-\frac{1075}{5^k}\right)=1075$

which is the upper limit to the population of the bees.

4 0

3 years ago

Paula walked on the treadmill for 12 minutes. The machine told her she had a total of 780 strides. What was her rate in strides

Cerrena [4.2K]

Answer:780/12=65

Step-by-step explanation:

7 0

4 years ago

What is the equation of the line that passes through the point (-3,5) and has a slope of -2

wariber [46]

Answer:

equation: y=-4x-7

Step-by-step explanation:

y=-4x+b

solve for b using given coordinates on the line (-3, 5)

5=-4(-3)+b

b=-7

6 0

4 years ago

Read 2 more answers