Answer:
the height of the tree is <em>15.49 m</em>
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Step-by-step explanation:
Step 1:
From the figure, we can determine ∠ATB by using the fact that the sum of all the angles in a triangle add up to 180°:
∠ ATB = 180° - 98° - 20°
∠ ATB = 62°
Step 2:
Therefore, using the law of sines, we can determine the height of the tree.
TB / sin(20°) = 40 / sin(62°)
TB = 40 × (sin(20°) / sin(62°))
<em>TB = 15.49 m </em>
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Therefore, the height of the tree is <em>15.49 m</em>
Let
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so

where
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

where
denotes the CDF of
, and
denotes the inverse CDF. We have

Similarly, because 20% of students obtain less than 40 marks, we have

so that

Then
are such that


and we find

5*1/5+1/5*15=4
1 + 3 =4
This should equal 4 if I did this correctly.