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Mazyrski [523]
2 years ago
13

A statue of Abraham Lincoln casts a 9-foot shadow at the same time the White House casts a 48-foot shadow. If the White House is

70 feet tall, how tall is the statue of Abraham Lincoln?​
Mathematics
2 answers:
jeka942 years ago
8 0

Answer: The statue, originally intended to be only 10 feet tall, was on further consideration enlarged so that it finally stood 19 feet tall from head to foot, the scale being such that if Lincoln were standing he would be 28 feet tall.

Step-by-step explanation: hope this helps

Ghella [55]2 years ago
7 0

Answer: 28 ft

Step-by-step explanation:

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hram777 [196]

Answer:

<h2>Function is y = x.</h2><h2>Domain: -3 \leq x \leq 2.</h2><h2>Range: -5 \leq y \leq 4.</h2>

Step-by-step explanation:

In the given image, the line passes through (-1, -1) and (1, 1).

Let the equation of the line is y = mx + c, where m is the tangent of the line and c is a constant.

Putting the co-ordinates of the points in the equation, we get -1 = -m + c and 1 = m + c

From the two equations we get, c = 0 and m = 1.

Hence, the function is y = x.

Domain is -3 \leq x \leq 2.

Range is -5 \leq y \leq 4

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3 years ago
An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Ghella [55]

Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

C) P(R&B) = 3/5 = 60%

Step-by-step explanation:

C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5

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