Answer:
a) The estimates for the solutions of 
are 
and 
.
b) The estimates for the solutions of 
are 
and 
Step-by-step explanation:
From image we get a graphical representation of the second-order polynomial 
, where 
is related to the horizontal axis of the Cartesian plane, whereas 
is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:
a)
There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:
,
b)
There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:
,
Answer:
First off, we look for which circles are open or closed.
We start with an open interval since the circle on the left is open and end with a closed interval since the circle on the right is closed.
Domain is all x values, Range is all y values
The graph shows the continous function going from -3 to 1 on the x axis.
According to the circles, this means our domain will be (-3,1].
Now, the range doesn't care about if its closed or not. So we can say the graph is on the y axis from -4 and 0. This means the range is -4<y<0
I used different notations for both just incase you need to represent your answer differently :)
-3<x<1 & (-3,1] . Range is [-4,0]. 0>y>-4 looks correct as-well.
Answer:
y=x7 X 5
Step-by-step explanation:
Answer:
-2
Step-by-step explanation:
Since the roots are known and the function is a quadratic function, we can write down the function:
y = (x+3)(x-2/3) since when the roots are plugged in, the function gives 0.
Standard form means that the function has to be expanded:
y = (x+3)(x-2/3) = 
y = 
The constant term is -2.
Do "42 + 12" Since 7 x 6 is 42 and 4 x 3 is 12.
