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polet [3.4K]
3 years ago
11

PLS HELP ME I NEED ANSWER FAST

Mathematics
2 answers:
erica [24]3 years ago
6 0

Step-by-step explanation:

(4x^3 - 4 + 7x) - ( 2x^3 - x - 8) = 2x^3 + 8x + 4

= (B)

(-3x^2 + x^4 + x) + (2x^4 - 7 + 4x) = 3x^4 - 3x^2 + 5x - 7

= (D)

(x^2 - 2x)(2x + 3) = 2x^3 - x^2 - 6x

= (A)

vaieri [72.5K]3 years ago
4 0

Answer:

it is a.

Step-by-step explanation:

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Dani’s estimate for the cost of tiling her bathroom is $50 plus $3 per square foot. She says that she can model the cost with a
jarptica [38.1K]
She is correct.

She starts with 50
Each square foot adds 3 dollars...
so Square feet can be represented by x, and cost will be y... giving this linear function:

y=3x+50.
4 0
3 years ago
Simplify: 20 sin(2x) cos(2x)
alexandr1967 [171]
Use the the double angle formula:
sin(2A)=2sin(A)cos(A)

substitute 2x for A, then
20sin(2x)cos(2x)=10(sin(2(2x))cos(2(2x))=10sin(4x)

8 0
3 years ago
Can someone please help me with this
Kryger [21]

Answer:

1. 96 inches squared

2. h=324

3. 85

Step-by-step explanation:

1. v=lwh

v=8•3•4

v=96

2. 345- 21

h=324

3. 1,012/12

=84.3

hope this helped!

7 0
3 years ago
A Confidence interval is desired for the true average stray-load loss mu (watts) for a certain type of induction motor when the
Vaselesa [24]

Answer:

A sample size of 35 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the width W as such

W = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large must the sample size be if the width of the 95% interval for mu is to be 1.0:

We need to find n for which W = 1.

We have that \sigma^{2} = 9, then \sigma = \sqrt{\sigma^{2}} = \sqrt{9} = 3. So

W = z*\frac{\sigma}{\sqrt{n}}

1 = 1.96*\frac{3}{\sqrt{n}}

\sqrt{n} = 1.96*3

(\sqrt{n})^2 = (1.96*3)^{2}

n = 34.57

Rounding up

A sample size of 35 is needed.

3 0
3 years ago
Help please, my teacher is horrible at explaning
Inessa05 [86]

10 hours and 10 minutes

6 0
4 years ago
Read 2 more answers
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