1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marta_Voda [28]
3 years ago
5

An open box is formed from a rectangular piece of cardboard, whose length is 3 inches more than it's width, by cutting 3 inch sq

uares from each corner and folding up the sides. if the volume of the box is to be 264 in^2, find the size of the original piece of cardboard. what are the original dimensions of the piece of cardboard
Mathematics
1 answer:
Feliz [49]3 years ago
4 0
3+264-2=265 inches

Hope this helps!!!!

:) :) :)
You might be interested in
Use the similar triangles to find the slope on the lines??? Hello plzzz
ch4aika [34]

Answer:

the slope is 1/4 my friend

4 0
2 years ago
Read 2 more answers
Rearrange to make x the subject of 4(x-3)/a=y
IrinaVladis [17]

Answer: x = a*y + 3

Step-by-step explanation:

To make x the subject of the equation, first, we open the bracket

4x - 12/a = y

Then cross multiply:

4x - 12 = a * y ( a*y means the product of the two variables)

Add 12 to both sides of the equation

4x = a*y + 12

Divide both sides by 4 to get the value of x

x = a * y + 12/4

x = a*y + 3

I hope this helps.

4 0
3 years ago
Estimate the perimeter of the figure to the nearest whole number.
Paha777 [63]

Answer:

The perimeter (to the nearest integer) is 9.

Step-by-step explanation:

The upper half of this figure is a triangle with height 3 and base 6.  If we divide this vertically we get two congruent triangles of height 3 and base 3.  Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles:  (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.

Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.

The lower half of the figure has the shape of a trapezoid.  Its base is 4.  Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle.  Using the Pythagorean Theorem, we get

(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10.  Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.

Then the perimeter consists of the sum 2√10 + 4 + 6√2.

which, when done on a calculator, comes to 9.48.  We must round this off to the nearest whole number, obtaining the final result 9.

4 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
Write the 2 digit number that matches the clue
Wittaler [7]
You can figure this out by setting up an equation and make

x= tens digit
y= ones digit

y + 8 =x (tens digit 8 more than ones)

also we know that 

y>0
x>0

since the 10s digit and 1s digit cannot be more than one number, we can say

0 < y > 10
0 < x > 10

since x has to be greater than 0 but less than 10, there is only one number that would fit into the equation for y

2 + 8 = 10
(y cannot equal 2 because than x is equal to 10 and it must be less than)

1 + 8 = 9 
( y can be 1 since x is less than 10)

so it would be 
y= 1
x= 9

the number would be 91

hope this helped!




5 0
3 years ago
Other questions:
  • Consider a six-sided die that is loaded so that numbers 2, 3, 4, 5 and 6 are all equally likely to appear, and 1 is three times
    13·1 answer
  • A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is
    5·1 answer
  • Which pair of rectangles is similar?<br><br> A. <br> B.<br> C.<br> D.
    10·1 answer
  • How do you know if a quadrilateral is a parallelogram?
    12·2 answers
  • If I have 777 pizzas and john eats 47.283 of the pizzas how many pizzas do i have but here's the thing I don't know how many piz
    11·1 answer
  • What is the slope of the line that passes through the points (9,6) and<br> (5, -8)?
    7·1 answer
  • Tina ate 21 starbursts. If she ate 35% of the package of Starbursts, how many Starbursts are in the package?
    7·1 answer
  • Whats the nth term of -1 -2 -3 -4 -5 ?
    6·1 answer
  • jasons high school played 14 football games this year the team won most of their games they were defeated during 2 games how man
    11·1 answer
  • A jar contains only dimes and nickels. The total number of coins in the jar is
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!