With in 1 standard deviation about the mean i.e. from -1 s.d. (left of mean) to +1 s.d. (right of mean), it covers 68% of the total area of curve.

So, the data that falls outside 1 standard deviation of the mean would be equal to (100% - 68%) i.e. 32%.

So, 32% is the final answer.

3 0

2 years ago

Help me plz

Sindrei [870]

96 seconds because if it shoots out 1/3 of a gallon per second we have to multiply that by 3. so it takes 3 seconds per gallon. so 3x32 is 96

8 0

2 years ago

Read 2 more answers

Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B31%20%5Ctimes%2031%7D%20" id="TexFormul

RideAnS [48]

Answer:

31 is the answers for the question

Step-by-step explanation:

please give me brainlest

6 0

2 years ago

Read 2 more answers

Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.

____ [38]

Let $z=-\sqrt3+i$ . Then

$|z|=\sqrt{(-\sqrt3)^2+1^2}=2$

$z$ lies in the second quadrant, so

$\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6$

So we have

$z=2e^{i5\pi/6}$

and the fourth roots of $z$ are

$2^{1/4}e^{i(5\pi/6+k\pi)/4}$

where $k\in\{0,1,2,3\}$ . In particular, they are

$2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}$

$2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}$

$2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}$

$2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}$

7 0

2 years ago