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Maru [420]
3 years ago
7

A marathon runner covers 42.0 km in 3h 45m. What was the runner's average speed

Mathematics
2 answers:
Roman55 [17]3 years ago
5 0

Answer:

I know you have to do s=d/t so 42/225=0.18

son4ous [18]3 years ago
3 0

Answer:

the average speed of the runner is 3.95 m/s

Step-by-step explanation:

if you take 3hr 45 min and turn it into minutes, which is 225. Then divide 225 by 42 and you should get your answer.

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shutvik [7]
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3 years ago
Find the greatest common factor and the least common multiple of 16 and 20. The prime factorizations of each number are given.
kykrilka [37]

Answer:

GCF 4, LCM 80

Step-by-step explanation:

Since both 16 and 20 have two 2s as factor, their greatest common factor is 4.

The LCM is found by multiplying all of the remaining factors by the LCM:

16 still has (2 x 2), 20 still has (5), times the GCF (4)  so 2 x 2 x 5 x 4 = 80.

5 0
2 years ago
Jon: 4b-1= -4+ 4b +3<br> is this no solution
anygoal [31]

Answer:

b=0

Step-by-step explanation:

4b-1=-4+4b+3

4b-4b=-4+3+1

b=0

5 0
3 years ago
Find the perimeter of the shape shown below.
sukhopar [10]

perimeter = turn of the figure

P = 6 + 3 + 4 + 4 + 3 + 6 + 3 + 4 + 3 = 36

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and 1 angle is 60° so the triangle is equilateral

 

7 0
2 years ago
Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u
Pachacha [2.7K]

Answer:

Fuel used = 111,303,473,760 MJ/year

Step-by-step explanation:

Power production = Fuel energy * Efficiency

1200 MW = Fuel energy * 0.34

Fuel energy = 1200 MW / 0.34 =3529.41 MW

This means it consumes 3529.41 MJ/s.

Per year, it operates 365 days, 24 hours a day, 3600 seconds an hour.

To calculate the fuel used annualy we have to multiplicate by all these factors

Fuel used = 3529.41 MJ/s * 3600 s/hour * 24 hours/day * 365 days/year

Fuel used = 111,303,473,760 MJ/year

4 0
3 years ago
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