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Maru [420]
3 years ago
7

A marathon runner covers 42.0 km in 3h 45m. What was the runner's average speed

Mathematics
2 answers:
Roman55 [17]3 years ago
5 0

Answer:

I know you have to do s=d/t so 42/225=0.18

son4ous [18]3 years ago
3 0

Answer:

the average speed of the runner is 3.95 m/s

Step-by-step explanation:

if you take 3hr 45 min and turn it into minutes, which is 225. Then divide 225 by 42 and you should get your answer.

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Someone please help me asap,
professor190 [17]

<em>Answer:</em>

Below is the complete proof.

<em />

<em>STATEMENT                              REASON  </em>

___________________________________________________

1. BC = EF                                    1. Given

2. AB + BC = AC                         2. Betweenness

3. AC > BC                                  3. Def. of segment inequality

4. AC > EF                                   4. Def. of congruent segments

Explanation:

  1. As BC = EF is given
  2. AB + BC = AC because it holds betweenness. Betweenness defines that if a point B is between points A and C, then the length of AB and the length of BC is equal to the length of AC.
  3. AC > BC because the Parts Theorem (Segments) mentions that if B is a point on AC between A and C, then AC > BC and AC>AB.
  4. AC > EF because BC = EF and if AC>BC, then it must be AC>EF.

<em>Keywords: segment, proof, statement</em>

<em> Learn more about proof, statement and reason from brainly.com/question/11775532</em>

<em> #learnwithBrainly</em>

5 0
4 years ago
Which of these is an example of an overdraft?
shutvik [7]
The correct answer is "Having $517.98 in you checking account and writing a check for $563.28" because you are spending more money than you have in your account.

Hope this helped :)
5 0
3 years ago
Find the vertex of f(x) = 12 - 41 +3
timofeeve [1]

-26 is the answer :)

6 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
PLEASE HELP
devlian [24]

Answer:

I think it is a 160o Angle

Step-by-step explanation:

7 0
3 years ago
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