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Bad White [126]
3 years ago
7

The function fx) = 3x - 20 underwent a translation resulting in the function g(x) = 3x - 26. Which rule describes the translatio

n?

Mathematics
1 answer:
Inga [223]3 years ago
8 0
This would be a horizontal shift 2 units to the right. When we right functions, we write (x-h) if it is a horizontal transition to the right, and (x+h) if it is a horizontal transition to the left. 

Since it is a horizontal transition 2 units to the right, the answer would be 

A. f(x-2)

I hope this has helped! :)

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The quotient of six times a number and 11
zhuklara [117]
This would look like 6x/11. Since the problem doesn’t state the answer then you would simply write the expression.
7 0
3 years ago
Steve wants to buy a new car and sees $12,000 car for which the dealership will provide 8% financing because of Steve's poor cre
blsea [12.9K]

5000

Step-by-step explanation:

because u have to add

5 0
2 years ago
Solve for x. Show each step of the solution. Show all work. 4.5(8-x)+36-2.5(3x+24)=102
sergejj [24]

4.5(8 - x) + 36 = 102 - 2.5(3x + 24)

36 - 4.5x + 36 = 102 - 7.5x - 60

72 - 4.5x = 42 - 7.5x

-4.5x + 7.5x = 42 - 72

3x = - 30

x = -30/3

x = -10 <===

Hope this helps!

4 0
3 years ago
Please answer this correctly
Ymorist [56]

B; 25.65+13.23+6.35=45.23

To do this mentally just add the 2 decimals places together first (1.23). Then just add the whole numbers (44). Then add the 2 numbers together, 44+1.23=45.23

8 0
3 years ago
1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle
zimovet [89]

Answer: \left |  2t-5\right |,\ 2,\ 2t-5

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

s(t)=t^2-5t+1

Speed of the particle is given by

\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left |  2t-5\right |

Acceleration of the particle is

\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2

velocity can be negative, but speed cannot

\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5

3 0
3 years ago
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