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3 years ago

All perfect squares are rational O True False

Mathematics

1 answer:

Dima020 [189]3 years ago

3 0

Answer:

true

Step-by-step explanation:

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Please help asap<br><br> solve x^4+5x^2+4=0

const2013 [10]

Answer:

$x=\pm i\text{ or }x=\pm2i$

Step-by-step explanation:

So we have the equation:

$x^4+5x^2+4=0$

Let's let u be equal to x². So:

$u^2+5u+4=0$

Factor:

$(u+1)(u+4)=0$

Zero Product Property:

$u+1=0\text{ or } u+4=0$

Subtract:

$u=-1\text{ or }u=-4$

Replace:

$x^2=-1\text{ or }x^2=-4$

Take square root:

$x=\pm\sqrt{-1}\text{ or }x=\pm\sqrt{-4$

Simplify:

$x=\pm i\text{ or }x=\pm2i$

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3 years ago

What is the equation of a horizontal line that passes through the point (3,-5)?

Kryger [21]

your answer for this question is y=c hope this helps

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2 years ago

Running at their respective constant rates, Machine X takes 2 days longer to produce w widgets than Machine Y. At these rates, i

Doss [256]

C. Hope this helps :)

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3 years ago

Help please! I don't get this.

slava [35]

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3 years ago

Read 2 more answers

Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the

sp2606 [1]

Given:

The given quadratic polynomial is :

$x^2-x-12$

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

$x^2-x-12$

Equate the polynomial with 0 to find the zeroes.

$x^2-x-12=0$

Splitting the middle term, we get

$x^2-4x+3x-12=0$

$x(x-4)+3(x-4)=0$

$(x+3)(x-4)=0$

$x=-3,4$

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

$x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}$

$x^2-(3+(-4))x+(3)(-4)$

$x^2-(-1)x+(-12)$

$x^2+x-12$

Therefore, the required polynomial is $x^2+x-12$ .

4 0

3 years ago