Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
1 answer:
Answer:
the time taken for the radioactive element to decay to 1 g is 304.8 s.
Step-by-step explanation:
Given;
half-life of the given Dubnium = 34 s
initial mass of the given Dubnium, m₀ = 500 grams
final mass of the element, mf = 1 g
The time taken for the radioactive element to decay to its final mass is calculated as follows;
Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.
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Answer:
y =
Step-by-step explanation:
Substitute x = - 2 into the equation and solve for y
3(- 2) + 5y = 8, that is
- 6 + 5y = 8 ( add 6 to both sides )
5y = 14 ( divide both sides by 5 )
y =
To solve this, we have to find the volume of the cylinder first. The formula to be used is 
Given:V= ?r= 6cmh= 10cm
Solution:
V= (3.14)(6cm)
x 10cmV= (3.14)(
) x 10cmV= (
) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
Given:V= ?r= 6cmh= 10cm
Solution:
V= (3.14)(6cm)
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.