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Citrus2011 [14]
2 years ago
15

I can’t figure this out

Mathematics
2 answers:
Rasek [7]2 years ago
5 0

Answer:

\dashrightarrow \: { \rm{28(y -  \frac{1}{7}) }} \\  \\ \dashrightarrow \: { \rm{28y -  \frac{28}{7} }} \\  \\ \dashrightarrow \: { \tt{28y - 4}}

Misha Larkins [42]2 years ago
4 0
28(y-1/7)= 28y-4
this deals with reducing fractions to their lowest terms.
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asambeis [7]

Answer:

x = -48

<em><u>hopefully i helped :)</u></em>

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3 years ago
Which of the following sets of lengths can Sean use to make a right triangle?
Aleks [24]

Answer:

{8 cm, 15 cm, 17 cm}

Step-by-step explanation:

we know that

The length sides of a right triangle must satisfy the Pythagoras Theorem

so

c^2=a^2+b^2

where

c is the greater side (the hypotenuse)

a and b are the legs (perpendicular sides)

<u><em>Verify each case</em></u>

case 1) we have

{5 cm, 15 cm, 18 cm}

substitute in the formula

18^2=5^2+15^2

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therefore

Sean cannot make a right triangle with this set of lengths

case 2) we have

{6 cm, 12 cm, 16 cm}

substitute in the formula

16^2=8^2+12^2

256=208 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 3) we have

{5 cm, 13 cm, 15 cm}

substitute in the formula

15^2=5^2+13^2

225=194 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 4) we have

{8 cm, 15 cm, 17 cm}

substitute in the formula

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6 0
3 years ago
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Hope this helps :)

7 0
3 years ago
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