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3 years ago

(7y^6z^4-4y^2)(-6yz^4)

Mathematics

1 answer:

rosijanka [135]3 years ago

7 0

I dont lnow the awnser of that but good luck on that!

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Find a number that is divisible by 2,3,5,6,9,and 10

FinnZ [79.3K]

90 and all of its multiples are.

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3 years ago

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Move the slider on the graph on the right to graph each function:

DedPeter [7]

Answer:

The domain is $x\geq 7$

The range is $y\geq 1$

Step-by-step explanation:

we have

$y=\sqrt{x-7} +1$

Find the domain

Remember that

The domain of a function is the set of all possible values of x

we know that the radicand of the function must be greater than or equal to zero

$x-7\geq 0$

solve for x

$x\geq 7$

therefore

The domain is $x\geq 7$

Find the range

Remember that

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

For x=7

The value of y is equal to

$y=\sqrt{7-7} +1=1$

The solution for y is the interval [1,∞)

therefore

The range is $y\geq 1$

6 0

2 years ago

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Hello please help with my question, I will give brainlyest!

lilavasa [31]

No, John is incorrect.

<h3>Correct work shown:</h3>

$\sf x^2 - 6x - 7 = 0$

$\sf x^2 - 6x = 7$

$\sf x^2 - 6x + 9= 7 + 9$

$\sf (x-3)^2= 16$

$\sf x-3=\pm \sqrt{16}$

$\sf x-3= \pm 4$

$\sf x= + 4 + 3 \quad or \quad x = -4 + 3$

$\sf x= 7 \quad or \quad x = -1$

The correct answer should be x = 7 or x = -1

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1 year ago

Exactly how many planes contain points J, K, and N? 0 1 2 3

Archy [21]

Answer:

Step-by-step explanation:

JK and KN is perpendicular.

Thus no planes contained them except 1

Which is a rectangle.

I hope this helps you :)

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2 years ago

Please help will give brainlist

adoni [48]

Answer:

It would be option 2.

Step-by-step explanation:

This is because option 1 does not have a irrational number that goes on indefinitely, option three has the square root of 25, which equals 5 meaning it is rational, and the last option also gives us rational choices. Therefore, the only possibility is that it would be option 2.

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2 years ago

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