4 years ago

(7y^6z^4-4y^2)(-6yz^4)

Mathematics

1 answer:

rosijanka [135]4 years ago

7 0

I dont lnow the awnser of that but good luck on that!

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victus00 [196]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Verify sin^4x-sin^2x=cos^4x-cos^2x is an identity

lara [203]

ANSWER

See below

EXPLANATION

We want to verify that,

${ \sin ^{4} x} - { \sin^{2} x} = { \cos ^{4} x} - { \cos^{2} x}$

To verify this identity, we can take the left hand side simplify it to get the right hand side or vice versa.

${ \sin ^{4} x} - { \sin^{2} x} =( { \sin ^{2} x} )^{2} - { \sin^{2} x}$

${ \sin ^{4} x} - { \sin^{2} x} ={ \sin ^{2} x}({ \sin ^{2} x} - 1)$

${ \sin ^{4} x} - { \sin^{2} x} ={ \sin ^{2} x} \times - (1 - { \sin ^{2} x})$

${ \sin ^{4} x} - { \sin^{2} x} =({1 - \cos^{2} x} )\times - ({ \cos^{2} x})$

${ \sin ^{4} x} - { \sin^{2} x} =({ \cos^{2} x} - 1 )\times ({ \cos^{2} x})$

We now expand the right hand side to get:

${ \sin ^{4} x} - { \sin^{2} x} = { \cos ^{4} x} - { \cos^{2} x}$

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A triangle has a base that measures 14 inches.

Sloan [31]

The answer to the question is 0.5

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3 years ago