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2 years ago

Plz help due tomorrow if correct ill give brailiest

Mathematics

1 answer:

Annette [7]2 years ago

3 0

C) the left side of the equation should be -15 + 3r after distributing.

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Solve the system using elimination: Help me please 12x - 8y = -12 6x + 4y = -30

LUCKY_DIMON [66]

12x - 8y = -12

6x + 4y = -30

Multiply the 2nd equation by 2, to make the Y coefficients opposite:

6x + 4y = -30 x 2 = 12x + 8y = -60

Now add the two equations:

12x -8y = -12 + 12x +8y = -60

= 24x = -72

Divide bothe sides by 24 to solve for x:

x = -72/24

x = -3

Now replace x with -3 in the first equation to solve for y:

12(-3) - 8y = -12

-36 - 8y = -12

Add 36 to each side:

-8y = 24

Divide both sides by -8 to solve for y:

y = 24 / -8

y = -3

X = -3 and y = -3

(-3,-3)

4 0

3 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago

The mark obtained by Belij in an exam is 28 out of 40, express his obtained marks in percentage

Brut [27]

Marks

= 28/40

= 28/40 × 2.5/2.5

= 70/100

= 70%

5 0

3 years ago

Read 2 more answers

Carmen rolls a cube with sides labeled A, B, C, D, E, and F.

Sav [38]

The number of possible outcomes is 29. ! hope this help hun <3

5 0

3 years ago

Divide 32 students into 2 groups so the ratio is two to five how many students with be in each group

Valentin [98]

Answer:

they can be divided into

2 groups of 16

4 groups of 8

8 groups of 4

16 groups of 2

5 0

2 years ago