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evablogger [386]
3 years ago
7

Please give the y intercept, slope, and x intercept of y=6x−7. All of them, not just one or two!

Mathematics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

Slope = 6, y intercept = -7, x intercept = 7/6

Step-by-step explanation:

Slope = 6

y intercept = -7

x intercept = 7/6

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We find volume through the following formula. Length*width*height. So if we multiply 3x4x5=60. Your answer will be 60 cubic feet or 60^3
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A card is drawn from a standard 52 card deck.What is the probability that the card is a red 8, given that the card is an 8?
Olenka [21]

Answer:D

Step-by-step explanation:

You know that the card picked is an 8, so forget the rest of the deck (they are trying to trick you into thinking it is 2 cards out of 52 cards). So there are 4 8's in a deck. 2 are red, 2 are black. You have a 2/4 chance of pulling a red.  2/4 = 1/2

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Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips.Urn II contains three red
lorasvet [3.4K]

Answer:

P(R_{2}) =\frac{10}{15} = 0.667

Step-by-step explanation:

Step 1: Understanding the possible events

Selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be completed in two ways:

A. Selecting a red chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

B. Selecting a white chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

Therefore total probability is:

                                         P(R_{2}) = P(A) + P(B)

Step 2: Probability of selecting either chip from Urn I

Urn I contains 2 reds and 4 white chips, that gives a total of 6 chips.

                                             P(R_{1}) = \frac{2}{6} =\frac{1}{3}

                                             P(W_{1}) = \frac{4}{6} =\frac{2}{3}

Step 3: Probability of selecting a red chip from Urn II

Urn II originally contains 3 reds and 1 white chip, that gives a total of 4 chips.

Remember: Once a chip is added from Urn I to Urn II the total number of chips will increase in the Urn II

Case 1: When a red chip is added from Urn I to Urn II

Red chips    = 4

White chips = 1

Total Chips  = 5

                                                  P(R_{2_1}) = \frac{4}{5}

Case 2: When a white chip is added from Urn I to Urn II

Red chips    = 3

White chips = 2

Total Chips  = 5

                                                  P(R_{2_2}) = \frac{3}{5}

Therefore the total Probability of selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be calculated as:

                                          P(R_{2}) = P(A) + P(B)

                           P(R_{2}) = P(R_{1}) . P(R_{2_1}) + P(W_{1}) . P(R_{2_2})

                                           P(R_{2}) =\frac{1}{3} . \frac{4}{5}  + \frac{2}{3} .\frac{3}{5}

                                             P(R_{2}) =\frac{4}{15}  + \frac{2}{5}

                                            P(R_{2}) =\frac{10}{15} = 0.667      

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3 years ago
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Ira Lisetskai [31]
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15% of x is 27, x= what?<br>please helppp meeee
natta225 [31]

Answer:

\huge \boxed{x=180}

Step-by-step explanation:

15% of x = 27

\sf 15\% \cdot x =27 \\\\\\ 0.15x=27 \\\\\\ Divide \ both \ sides \ by \ 0.15. \\\\\\ \frac{0.15x}{0.15}  = \frac{27}{0.15} \\\\\\ x = 180

15% of 180 is 27.

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3 years ago
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