Answer:
huhhh i dont understand fully
Step-by-step explanation:
Answer:
c. is the answer becuase since it is exterior they are talking about the outside of the parellel lines.
Step-by-step explanation:
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).

Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is =
g/L
Outgoing rate =



Integrating both sides

[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram


Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get









Therefore the concentration of salt in the incoming brine is 1.73 g/L
Answer:
Step-by-step explanation:
4 + 2x < 6 + 6x
4 - 4x < 6
-4x < 2
x > -1/2
Answer:
Good luck :)
Step-by-step explanation:
S=2πrh+2πr ²
subtract 2πr ² from each side
S -2πr ² = 2πrh
divide by 2πr from each side
(S -2πr ² )/ 2πr = h