Answer:
Ticket price = $170
Number of tickets sold = 850
Step-by-step explanation:
Let X= the number of $10 price reduction and the number of 50 tickets increase
Let p= price per ticket
Let q= number of tickets sold
Let R= revenue
Let p(x) = price of ticket now sold
Let q(x) = number of tickets now sold
R(x) = p(x) * q(x)
P(x) = 300 - 10x
q(x)= 200 + 50x
R(x) = (300 -10x) (200 - 50x)
= 60000 + 15000x - 2000x - 500x^2
= 60000 + 13000x - 500x^2
Differentiate with respect to x
dR(x)/dx = 13000-1000x
Put dR(x)/dx = 0
0= 13000 - 1000x
1000x = 13000
Divide through by 1000
1000x/1000 = 13000/1000
x = 13
Therefore x = 13 for $10 price reduction and 50 tickets increase
p(x) = 300 - 10x
= 300 - 10*13
= 300 - 130
= $170
q(x) = 200 + 50x
= 200 + 50*13
= 200 + 650
= 650
Maximum Revenue = p(x) * q(x)
= 170 * 850
= $144,500
For 13 reductions, we have $170 price reduction and 850 ticket sales
f(2) is greater than g(2) and f(-2) is less than g(-2)
Answer:
1/16 of a gallon
Step-by-step explanation:
total = 1/4 gallon
split into 4 containers
1/4 ÷ 4 = 1/4 • 1/4 = 1/16
1/16 of a gallon
A three-dimensional box-shaped figure, with six identical square faces
