Answer:
21p - 10r +123
Step-by-step explanation:
Answer:
1st pair of complementary angles: ∠c + ∠d
2nd pair of complementary angles: ∠g + ∠h
Step-by-step explanation:
the two solid lines are perpendicular, creating 4 right angles
1st pair of complementary angles: ∠c + ∠d
2nd pair of complementary angles: ∠g + ∠h
Call this piece of the plane S. Parameterize S by the vector function
s(u, v) = u i + v j + (28 - 2u - 3v)/4 k
with 1 ≤ u ≤ 4 and 2 ≤ v ≤ 6. Take the normal vector to S to be
∂s/∂u x ∂s/∂v = 1/2 i + 3/4 j + k
which has norm √((1/2)^2 + (3/4)^2 + 1^2) = √29/4
The area of S is then
it is 1 2 twelve I can end without 20 word my friend so deal with it
Step-by-step explanation:
the Domain of the function
=> Df ={1, 3, 5, 7, 9}
the Range of the function
=> Rf ={0, 1, 2, 3, 4}