The discount price of a hat is $24. whats the regular price

joyce has between 25 to 75 coloured beads. when she makes them into groups of 9, 8 beads are left out. when she groups into grou

hoa [83]

Answer:

Joyce has total 62 colored beads.

Step-by-step explanation:

For making groups of 9, let the number of beads be x.

total beads = 9x + 8

For making groups of 8, let the number of beads be y.

total beads = 8y + 6

As the total number of beads in both cases are same so,

9x + 8= 8y + 6

or, 9x-8y = -2

Now lets check the values through hit and trial;

First check; x=6, y=7

9*6 - 8*7 = -2

or, 54- 56 = -2

or, -2 =-2

This satisfies our equation.

Hence; Total beads = 9*6 + 8 = 62

The total number of beads joyce had is 62.

7 0

3 years ago

Read 2 more answers

10. How can you use similar triangles to solve real-world problems?

8090 [49]

Similar triangles can be extremely useful in architecture. For example, similar triangles can help represent doors and how far they swing. Also when using shadows that make the triangles you can use them to find the height of an actual object they can be used to construct many architectural designs and monuments for e.g, bridges. You can also determine values that you can’t directly measure. For e.g you. Can measure the length of your shadow and a tree’s shadow on a sunny day.

6 0

3 years ago

Compare the perimeters of the two regular figures. Which statement is true?

adell [148]

Answer:

(A). The perimeter of the octagon is greater than that of the hexagon.

Step-by-step explanation:

Since, hexagon consists of 6 sides and 6 angles, thus the measure of one angle of the hexagon will be= $\frac{(n-2){\timeS}180^{\circ}}{6}$

= $\frac{(6-2){\timeS}180^{\circ}}{6}$

= $\frac{(4){\timeS}180^{\circ}}{6}$

= $120^{\circ}$

Now, since MQ is the angle bisector of the one of the angle of the hexagon, therefore ∠QMP=60°.

Now, from ΔQMP. we have

$\frac{MP}{MQ}=cos60^{\circ}$

$MP=\frac{1}{2}$

Thus, the perimeter of the hexagon is:

$P=12{\times}MP$

$P=12{\times}\frac{1}{2}$

$P=6 units$

Thus, the perimeter of hexagon is 6 units.

Also, Since, octagon consists of 8 sides and 8 angles, thus the measure of one angle of the octagon will be= $\frac{(n-2){\timeS}180^{\circ}}{8}$

= $\frac{(8-2){\timeS}180^{\circ}}{8}$

= $\frac{(6){\timeS}180^{\circ}}{8}$

= $135^{\circ}$

Now, since AP is the angle bisector of the one of the angle of the octagon, therefore ${\angle}PAC=cos\frac{135}{2}$ .

From ΔAPC, we have

$AC=cos\frac{135}{2}$

Now, Perimeter of octagon is:

$P=16{\times}cos\frac{135}{2}$

$P=16{\times}0.382$

$P=6.122 units$

Thus, the perimeter of octagon is 6.122 units.

Now, the perimeter of octagon is greater than perimeter of the hexagon, thus option A is correct that is The perimeter of the octagon is greater than that of the hexagon.

4 0

3 years ago

Vertx: (3, 1)<br> Focus: (3,-1)

enot [183]

Answer:

i need help with this one two

Step-by-step explanation:

.

5 0

3 years ago

What is the equivalent expession of 24x-78y

pickupchik [31]

When you find the GCF (Greatest Common Factor), which is 6 you simplify both by 6 and get 4x-13y

6 0

3 years ago