Dang if not digit is used more than once then i go with 720 :)
Answer:
a3+13a
Step-by-step explanation:
sorry I don't know how to solve this
Answer:
Step-by-step explanation:
x^3 - 8x² - x + 8 =0
x^3 - 8x² - (x - 8 )=0
x²(x-8) - (x-8) = 0
(x-8)(x² -1) =0
x-8 = 0 or x² - 1 = 0
x-8=0 or (x-1)(x+1)=0
x=8 x=1 or x=-1
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
Answer: 18.33 ppg
Step-by-step explanation:
He played three games
18+29+8=55
55/3=18.33
