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yanalaym [24]
2 years ago
6

A parking lot in the shape of a trapezoid has an area of 126 square meters. The length of one base is 8 meters, and the length o

f the other base is 10 meters. What is the width of the parking lot?
Group of answer choices
7 meters

14 meters

10 meters

28 meters
Mathematics
1 answer:
Nata [24]2 years ago
3 0

Answer:

14

Step-by-step explanation:

126/9=14

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The diagram shows a logo​
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Answer/Step-by-step explanation:

✔️Find EC using Cosine Rule:

EC² = DC² + DE² - 2*DC*DE*cos(D)

EC² = 27² + 14² - 2*27*14*cos(32)

EC² = 925 - 756*cos(32)

EC² = 283.875639

EC = √283.875639

EC = 16.85 cm

✔️Find the area of ∆DCE:

Area = ½*14*27*sin(32)

Area of ∆DCE = 100.15 cm²

✔️Since ∆DCE and ∆ABE are congruent, therefore,

Area of ∆ABE = 100.15 cm²

✔️Find the area of the sector:

Area of sector = 105/360*π*16.85²

Area = 260.16 cm² (nearest tenth)

✔️Therefore,

Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)

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