A. 2,464 cm^2<br> B. 2,364 cm ^2<br> C. 1,464 cm^2<br> D. 1,364 cm^2

On a standardized exam, the scores are normally distributed with a mean of 165 and astandard deviation of 40. Find the z-score o

vladimir1956 [14]

The Z-score is calculated by the formula below

$\begin{gathered} z-score=\frac{(x-\mu)}{\sigma}_{} \\ \mu=\operatorname{mean} \\ \sigma=s\tan dard\text{ deviation} \\ x=\text{score} \end{gathered}$

Step 2: Substitute the given parameters in the formula

$\begin{gathered} z-\text{score}=\frac{145-165}{40} \\ Z=-\frac{20}{40} \\ Z=-\frac{1}{2} \\ Z=-0.5 \end{gathered}$

Hence, the z-score of a person who scored 145 on the exam is -0.5

8 0

1 year ago

Darren's town voted on a new speed limit. 10% of the 20 votes were in favor of the new speed limit. How many votes were in favor

Westkost [7]

10% of 20
20/10 = 2
2 votes were in favour

3 0

3 years ago

Is 12 posters for 36 students equivalent to 21 posters to 63 student

Dmitry [639]

yes.

this is division. 36 divided by 12 is 3. 63 divided by 21 is 3.

3 0

3 years ago

Read 2 more answers

"A study conducted at a certain college shows that 56% of the school's graduates find a job in their chosen field within a year

KiRa [710]

Answer:

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they find a job in their chosen field within one year of graduating, or they do not. The probability of a student finding a job in their chosen field within one year of graduating is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

56% of the school's graduates find a job in their chosen field within a year after graduation.

This means that $p = 0.56$

Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

This is $P(X \geq 1)$ when n = 6.

Either none find a job, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.56)^{0}.(0.44)^{6} = 0.0073$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0073 = 0.9927$

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

8 0

3 years ago

The top of a coffee table is the shape of a rectangle the length of the top of the coffee table is 3.5 feet in the area is 10.5

velikii [3]

Area=length times width

area=10.5
length=3.5

10.5=3.5 times width
divide both sides by 3.5
3=width
width=3ft

3 0

3 years ago

A. 2,464 cm^2 B. 2,364 cm ^2 C. 1,464 cm^2 D. 1,364 cm^2