The true statement about right-angle triangle ABC is that: A. sin(A) = cos(C) and cos(A) = sin(C).
<h3>How to apply basic trigonometry?</h3>
In order to determine the angles, we would apply basic trigonometry. From the diagram of the right-angled triangle shown below, we can deduce the following parameters:
By applying the basic trigonometry functions, we have:
sin(A) = Opp/Hyp = a/c.
sin(C) = Opp/Hyp = c/b.
cos(A) = Adj/Hyp = c/b.
cos(C) = Adj/Hyp = a/c.
From the above, we can logically deduce that sin(A) is equal to cos(C) and cos(A) is equal to sin(C).
Read more on sine trigonometry here: brainly.com/question/20367642
#SJP1
(9,13) would be another point that the line passes through.
<span>coordinates m' is going to be (-2/5,-4/5)
</span><span>coordinates n' is going to be (1/5,1)
</span>I just took the test i hope this helps!
bro 1234567890987654321 dude
The area of a regular hexagon is
... A = (3√3)/2×s² . . . . . where s is the side length
Of course, the 6-sided figure will have a side length that is 1/6 of the perimeter.
... s = (48 in)/6 = 8 in
... A = (3√3)/2×(8 in)² = 96√3 in² . . . area of your regular hexagon