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3 years ago

What is 2 + 2 + 2 + 2 + 2

Mathematics

2 answers:

charle [14.2K]3 years ago

8 0

Answer:10

Step-by-step explanation:

iren2701 [21]3 years ago

3 0

Answer:

2+2=4+2=6+2=8+2=10

the answer is 10 lol

Step-by-step explanation:

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A circular garden has a circumference of 63 yards. Lars Is digging a straight line along a diameter of the garden at a rate of 5

k0ka [10]

Answer:

4 hours

Step-by-step explanation:

f the circumference of the circular garden =63 yards

Circumference of a Circle =2πr=πd (d=diameter)

Therefore:

πd= 63

diameter of the circular garden =63/3.14=20 yards

If he digs at a rate of 5 yards per hour, the time required to dig across the garden will be:

20 yards/5 yard per hours = 4 hours

It will take him 4 hours to dig across the circular garden.

7 0

2 years ago

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

Read 2 more answers

Which equation can be used to find the measure of the angles below if line a is parallel to line b?

IgorC [24]

I think the answer is c

5 0

3 years ago

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Identify the solution set of 3 In 4 = 2 In x. -{6} -{-8,8} -(8)

o-na [289]

Option C: The solution set is $\{8\}$