Answer:
B: y = − (x − 3)² + 2
Step-by-step explanation:
You can check this using a graphing calculator, but it has a vertex of (3,2)
Answer:
2. 8:45am to 5:15pm
Step-by-step explanation:
Looking at the table of John's times, he arrived at 8:42am and left at 5:14pm. If you are rounding to the nearest quarter hour, or 15 minutes, you time would need to be at the hour, 15 minutes after, 30 minutes after or 45 minutes after. Given those options, the closest times would be 8:45am and 5:15pm.
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer: $0.268
Step-by-step explanation: 5.36 divided by 20 = 0.268
Answer: 56 large cars and 86 small cars.
Step-by-step explanation:
Let's call:
: the number of large cars.
: the number of small cars.
Then, you can set up the following system of equations:
You can use the Elimination Method:
- Multiply the first equation by -4.0
- Add both equations.
- Solve for l.
≈
Substitute 
into one of the original equations and solve for <em>s:</em>
<em> </em>
