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aivan3 [116]
3 years ago
10

A solid reactant is placed into a beaker of a warm water. The liquid vigorously bubbles as the solid dissolves into the solution

. What will most likely happen if the temperature of the liquid is slightly reduced?
Chemistry
1 answer:
Nataly [62]3 years ago
3 0

Answer:

Fewer bubbles will be produced because of fewer collisions of reactant molecules

Explanation:

As the solid dissolves into the solution after the liquid has been vigorously bubbled, if the temperature of the liquid is reduced a little, what will happen is that fewer bubbles will be produced as a result of lesser amount of collisions occurring between the reactant molecules

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Temperature and pressure at the earth's surface are minimal compared to what they are at depth. With sediments, they become converted to rocks or become lithified by burial which subjects them to higher temperature and pressure. If the temperature and pressure become too great, then the sediments will be converted to metamorphic rocks. Basically the rocks or sediments are changing in order to be in equilibrium with the new conditions.
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a car manufacturer claims that since their car engines dont get very hot, more of the gasolines energy can be used to make the c
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Newton’s 2nd law? Maybe I’m not completely sure
7 0
4 years ago
a gas has a volume of 350 cubic centimeters at 740 mmHg. how many cubic centimeters will the gas occupy at a pressure of 900 mmH
Harrizon [31]

Answer: 287.8 cm3

Explanation:

Given that:

Initial volume of gas V1 = 350 cm3

Initial pressure of gas P1 = 740 mmHg

New volume V2 = ?

New pressure P2 = 900 mmHg

Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

740 mmHg x 350 cm3 = 900mmHg x V2

V2 = (740 mmHg x 350 cm3) /900mmHg

V2 = 259000 mmHg cm3 / 900mmHg

V2 = 287.8 cm3

Thus, the gas will occupy 287.8 cubic centimeters at the new pressure.

3 0
3 years ago
Give a possible explanation for the relative amounts of the isometric methyl nitrobenzoates formed in the nitration reaction. Co
vovikov84 [41]

Answer:

The electrophilic aromatic substitution reaction nitration is used to nitrate methyl benzoate and acetanilide with a nitronium ion. Crystallization was used to purify the product. The melting point was used to determine its purity and the regiochemistry of the products.

Explanation:

Methyl m-Nitrobenzoate is formed in this

reaction rather that ortho/para isomers

because of the ester group of your starting

product of methylbenzoate. The functional

group of ester is a electron withdrawing group

causing nitrobenzene (N02) to become in the

meta position. Thus N02 is a deactivating

group causing itself to be a meta director.

Basically you must look at the substituents

that are attached to your starting benzene ring

in order to figure out whether your reaction

with be ortho/para directors or meta

directors. If the substituents are electron

withdrawing groups then you will be left with

meta as your product but if your substituents

are electron donating groups then your

product will be ortho/para.

4 0
3 years ago
Write the complete ionic equation for the reaction that takes place when aqueous solutions of strontium hydroxide and lithium ph
Nesterboy [21]

Answer : The net ionic equation will be,

3Sr^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Sr_3(PO_4)_2(s)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

3Sr(OH)_2(aq)+2Li_3​PO_4(aq)\rightarrow 6LiOH(aq)+Sr_3(PO_4)_2(s)

The ionic equation in separated aqueous solution will be,

3Sr^{2+}(aq)+6OH^{-}(aq)+6Li^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Sr_3(PO_4)_2(s)+6Li^+(aq)+6OH^{-}(aq)

In this equation, Li^+\text{ and }OH^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

3Sr^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Sr_3(PO_4)_2(s)

4 0
3 years ago
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