Answer: f(x) = x9h(x)
h(-1) = 2
h'(-1) = 5
We need to find h(x) first. Once we have h(x), we can find the derivative of f(x). Then evaluate the derivate when x = -1.
We know that derivative is the slope of the tangent line. In this case, the slope of the line tangent to h(x) at x=-1 is 5.
h(-1) = 2 has a coordinate point of (-1, 2).
2 = 5(-1) + b
2 = -5 + b
7 = b
h(x) = 5x + 7 -----> equation of the tangent line
f(x) = x9(5x + 7)
f(x) = 5x10 + 7x9
Take the derivative of f(x).
f'(x) = 50x9 + 63x8
f'(-1) = 50(-1)9 + 63(-1)8
f'(-1) = -50 + 63
f'(-1) = 13
Step-by-step explanation:
Answer:
y = 5x - 8
Step-by-step explanation:
10x -16 = 2y
y = 10/2x - 16/2
y = 5x - 8
Answer:
Step-by-step explanation:
From the given information:
Let represent 
as the first player getting an ace
Let 
to be the second player getting an ace and
as the second player not getting an ace.
So;
The probabiility of the second player not getting an ace and the first player getting an ace can be computed as;
Let's determine the probability of getting an ace in the first player
i.e
To determine the probability of the second player getting an ace and the first player getting an ace.
Thus, the conditional probability that the second player has no aces, provided that the first player declares affirmative is:
Therefore;
for n= 2
for n= 10
for n = 100
