Write the converse.

A Line passes through the .4 -6 and has a slope of -3 and four which is the equation of the line

Elan Coil [88]

Answer:

(in the image)

Step-by-step explanation:

I'm not sure I understood your question completely but I hope this helps.

7 0

2 years ago

Which of the following are equivalent to 140%? 0.14 5/7 1 2/5 1.4

Alika [10]

1.4

To make a percent a decimal, divide it by 100.

140 ÷ 100

= 1.4

♧

5 0

2 years ago

Which system of equations is represented by the matrix below

malfutka [58]

Answer:

Option A.

Step-by-step explanation:

The given matrix is

$\left[\left.\begin{matrix}4 & 5\\ 7 & -4\end{matrix}\right|\begin{matrix}-16\\ 23\end{matrix}\right]$

We need to find the system of equations which is represented by the matrix.

In the given matrix first row represents the first equation and second row represents the second equation of the system of equations.

Let two variables are x and y.

First column represents the coefficients of x and second column represents the coefficients of y.

Numbers on the right side of the matrix represents the numbers which are right side of the equations.

Now, the required equations are

$4x+5y=-16$

$7x-4y=23$

Therefore, the correct option is A.

4 0

2 years ago

A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f

krok68 [10]

✰ Concept Used :-

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In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

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✰ Given Information :-

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Hypotenuse = 22 ft.
Base = 10 ft.

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✰ To Find :-

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The value of side or the perpendicular

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✰ Formula Used :-

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$\star \: \underline{ \boxed{ \purple { \sf {Side}^{2} = {Hypotenuse}^{2} - {Base}^{2} }}} \: \star$

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✰ Solution :-

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$\sf \longrightarrow {Side}^{2} = {(22 \: ft)}^{2} - {(10 \: ft)}^{2} \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {484 \: ft}^{2} - {100 \: ft}^{2} \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{2} = {384 \: ft}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \sqrt{ {384 \: ft}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow {Side}^{} = \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\$