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julsineya [31]
3 years ago
12

State the negation of the following statement: Lines a and b are parallel.

Mathematics
2 answers:
klemol [59]3 years ago
3 0
The answer would be "Lines A and B are not Parallel"

I hope this helps you! If it does, please rate it as Brainliest :D
Wittaler [7]3 years ago
3 0

Answer: Lines a and b are not parallel.

Step-by-step explanation:

  • The negation of any statement is known as the logic complement of the statement.

The negation of any statement p is given by :-

\sim p (not p)

The given statement :  Lines a and b are parallel.

To write the negation of the statement we just write opposite of the statement.

Then , the negation of this statement is given by :-

Lines a and b are not parallel.

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A quadratic function is shown. f(x) = -x^2+7x-12 one factor of this function is (x-4). What is the other factor of the quadratic
Alexus [3.1K]

Answer:

The other term is<u> (x-3)</u>

Step-by-step explanation:

The quadratic function is:

f(x)=-x^{2}+7x-12

Factoring this function we will have:

f(x)=-(x-4)(x-3)

Therefore, the other term is<u> (x-3).</u>

I hope it helps you!

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3 years ago
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Alenkasestr [34]

Answer:

I hope this is helpful

Step-by-step explanation:

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4 0
2 years ago
X-y=5 and x^2y=5x+6​
sergeinik [125]

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

<h3>How to solve a system of equations</h3>

In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

To learn more on nonlinear equations: brainly.com/question/20242917

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8 0
2 years ago
What is the answer to 9x-7i&gt;3(3x-7u)
Jlenok [28]

Answer:

undefined

Step-by-step explanation:

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#19. state the possible number of imaginary numbers of f(x) = 7x3 - x2 + 10x - 4
guapka [62]
7x3=21-2=19+10=29-4=25
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