Answer:
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so
Now, find the margin of error M as such
In which
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 5.4 - 0.04 = 5.36 years.
The upper end of the interval is the sample mean added to M. So it is 5.4 + 0.04 = 5.44 years.
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
Answer:
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Step-by-step explanation:
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Answer:
Part A: The total is 57.58
Part B: 19.19 each
Step-by-step explanation:
Part A: 15(3) +3.50(3)=55.50
55.50 plus the 3.75% tip (not really addition i dont know how to find a percentage so i looked that part up) but it come out to $57.58
Part B: 57.58 divided by 3 is $19.19 ( I do 3 because Maria and 2 more friends)
Hope it helps and that it is 100% correct dont come at me if something is wrong with my math