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Vika [28.1K]
3 years ago
9

Panuto: Isulat ang TAMA kung ang pahayag ay tumutukoy sa naging

Advanced Placement (AP)
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

mali

tama

tama

mali

tama

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¿Cómo se produce una contractura muscular?
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What's the question? (Plz type in English)
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Please show steps and explain
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Answer:

\frac{n-6}{3n} = \frac{n-5}{3n+1} \\\\\frac{n-6}{3n} - \frac{n-5}{3n+1} = 0\\\\\frac{(3n+1)(n-6)-3n(n-5)}{3n(3n+1)} = 0\\\\(3n+1)(n-6)-3n(n-5) = 0\\\\3n^2-18n+n-6-3n^2+15n=0\\\\3n^2-3n^2-18n+n+15n-6=0\\\\-2n-6=0\\\\2n+6=0\\\\2n=-6\\\\n=-3

You can solve this equation by applying the zero product rule.

Firstly, you equate the expression to 0 in order to combine both fractions into one. As shown in Step 2, you find the LCM of both fractions and multiply accordingly. In this case, the LCM of both fractions is 3n(3n+1). Hence you cross multiply.

Next, you eliminate the denominator in order to solve the equation more conveniently. As you multiply the fraction by the denominator on the LHS, you do that to the RHS as well to maintain balance. 0×3n(3n+1)=0, hence Step 3.

Then, you expand the parentheses using the distributive law of multiplication, resulting in a quadratic equation.

Lastly, you solve the quadratic equation.

The answer is n=-3

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3 years ago
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I would say, the teddy drop mission.

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What feature do plants have that provide structure and form?
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Plants have rigid tubes made of cellulose that provides structure and form.

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Slope integrals for calculus, having trouble need all the help I can get
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(1) The integral is straightforward; <em>x</em> ranges between two constants, and <em>y</em> ranges between two functions of <em>x</em> that don't intersect.

\displaystyle\int_{-2}^1\int_{-x}^{x^2+2}\mathrm dy\,\mathrm dx

(2) First find where the two curves intersect:

<em>y</em> ² - 4 = -3<em>y</em>

<em>y</em> ² + 3<em>y</em> - 4 = 0

(<em>y</em> + 4) (<em>y</em> - 1) = 0

<em>y</em> = -4, <em>y</em> = 1   →   <em>x</em> = 12, <em>x</em> = -3

That is, they intersect at the points (-3, 1) and (12, -4). Since <em>x</em> ranges between two explicit functions of <em>y</em>, you can capture the area with one integral if you integrate with respect to <em>x</em> first:

\displaystyle\int_{-4}^1\int_{y^2-4}^{-3y}\mathrm dx\,\mathrm dy

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\displaystyle\int_1^5\int_0^{\frac1{x^2}}\mathrm dy\,\mathrm dx

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