Answer:
![5A + 4P = 10](https://tex.z-dn.net/?f=5A%20%2B%204P%20%3D%2010)
![5A + 5P = 11](https://tex.z-dn.net/?f=5A%20%2B%205P%20%3D%2011)
1 apple costs $1.2
1 pear costs $1
Step-by-step explanation:
Represent Apples with A and Pears with P
For the person in my front, the expression is:
![5A + 4P = 10](https://tex.z-dn.net/?f=5A%20%2B%204P%20%3D%2010)
For me, the expression is
![5A + 5P = 11](https://tex.z-dn.net/?f=5A%20%2B%205P%20%3D%2011)
Hence, the system of equation is:
![5A + 4P = 10](https://tex.z-dn.net/?f=5A%20%2B%204P%20%3D%2010)
![5A + 5P = 11](https://tex.z-dn.net/?f=5A%20%2B%205P%20%3D%2011)
Solving for the values of A and P.
Substract equation (2) from (1)
![5A - 5A + 4P - 5P = 10 - 11](https://tex.z-dn.net/?f=5A%20-%205A%20%2B%204P%20-%205P%20%3D%2010%20-%2011)
![-P = -1](https://tex.z-dn.net/?f=-P%20%3D%20-1)
![P = 1](https://tex.z-dn.net/?f=P%20%3D%201)
<em>Hence, 1 pear costs $1</em>
Substitute 1 for P in ![5A + 4P = 10](https://tex.z-dn.net/?f=5A%20%2B%204P%20%3D%2010)
![5A + 4 * 1 = 10](https://tex.z-dn.net/?f=5A%20%2B%204%20%2A%201%20%3D%2010)
![5A + 4 = 10](https://tex.z-dn.net/?f=5A%20%2B%204%20%3D%2010)
![5A = 10 - 4](https://tex.z-dn.net/?f=5A%20%3D%2010%20-%204)
![5A = 6](https://tex.z-dn.net/?f=5A%20%3D%206)
![A = \frac{6}{5}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B6%7D%7B5%7D)
![A = \$1.2](https://tex.z-dn.net/?f=A%20%3D%20%5C%241.2)
<em>Hence, 1 apple costs $1.2</em>
Answer:
3x ≤ 12 x≤4
Step-by-step explanation:
If Antonio has only $12 to spend on the milk, then the inequality sign should be less than or equal to. Since he can not go over 12. So from this you must figure out how many cartons he can buy. 12/3 = 4. So the maximum amount he can buy is 4 cartons.
![\rm ax^2=bx](https://tex.z-dn.net/?f=%5Crm%20ax%5E2%3Dbx)
apply subtraction,
![\rm ax^2-bx=0](https://tex.z-dn.net/?f=%5Crm%20ax%5E2-bx%3D0)
factor out an x,
![\rm x(ax-b)=0](https://tex.z-dn.net/?f=%5Crm%20x%28ax-b%29%3D0)
apply your Zero-Factor Property,
![\rm x=0\qquad\qquad\qquad ax-b=0](https://tex.z-dn.net/?f=%5Crm%20x%3D0%5Cqquad%5Cqquad%5Cqquad%20ax-b%3D0)
And then solve for x in each case.
Clearly the first factor gives us x=0.
In the other factor tho,
add b,
then divide by a,
Answer:
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