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3 years ago

1. 36(a+b)^2 - 49(a-b(^2

Mathematics

1 answer:

Brums [2.3K]3 years ago

8 0

Answer:

-13a^2 + 170ab - 13b^2.

Step-by-step explanation:

1. 36(a+b)^2 - 49(a-b)^2

This is the difference of 2 squares: a^2 - b^2 = (a + b)(a - b).

36(a+b)^2 - 49(a-b)^2

= (6(a + b) + 7(a - b))( 6(a + b) - 7(a - b))

= (6a + 7a + 6b - 7b)( 6a - 7a + 6b + 7b)

= (13a - b)(-a + 13b)

If you require the expansion of this it is:

-13a^2 + 170ab - 13b^2.

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Solving rational equations<br><br> solve for x: 3/x-4=7/x

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Solving the rational equation $\frac{3}{x-4}=\frac{7}{x}$ the value of x is 7

Step-by-step explanation:

We need to solve rational equation: $\frac{3}{x-4}=\frac{7}{x}$ and find value of x.

Solving:

$\frac{3}{x-4}=\frac{7}{x}$

Cross multiplying:

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So, value of x = 7.

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Read 2 more answers

PPPLLLLEEEAASSSEEEE HHHEEEELLLLPPPPP!!!!!!!

Yuliya22 [10]

Answer:

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Step-by-step explanation:

Because the center of dilation is at (0, 0), or the origin, we can just multiply the x and y values of each point by the scale factor of 13.

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Read more on Brainly.com - brainly.com/question/11445104#readmore

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3 years ago

A right triangle has an area of 18 square inches.If the triangle is an isosceles triangle, what are the lengths of the legs of t

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