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Goryan [66]
3 years ago
10

PLEASE HURRY!!!! Which ratio is equivalent to 4, (point)

Mathematics
2 answers:
g100num [7]3 years ago
5 0
08:32 i did this on a text and it’s was right hope this helps you:)
anyanavicka [17]3 years ago
4 0

Answer:

08:32

Step-by-step explanation:

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The Distributive Property to express 14 + 63
Ksivusya [100]
7(2+9) would be the answer as 7 is the greatest common factor
7 0
3 years ago
I am genuinely lost ..... pls dont give me pdfs or links
Nutka1998 [239]

Answer:

There are 60 6th graders in band.

Step-by-step explanation:

Let x represent the number of 6th graders in band. If there are 25% more in 7th grade, you can write it as (5/4)x. (You could also say 1.25x, but I think fractions would be easier in this situation.) Set up an equation:

x+(5/4)x=135

Now solve for x.

(4/4)x+(5/4)x=135

(9/4)x=135

(1/4)x=15

x=60

There are 60 6th graders in band.

Hope I could help you!

3 0
3 years ago
**PLEASE HELP**
Nikitich [7]
Total area of zone and playground, (x+50)(x+30);
and this whole area is twice the area of the playground, consistent with description.
highlight_green%28%28x%2B50%29%28x%2B30%29=2%2A50%2A30%29;
Solve for x.
3 0
3 years ago
(ONLY TWO CAPITAL LETTERS) PLEASE ANSWER CORRECTLY!!!!!! WILL MARK BRIANLIEST!!!!!!!! URGENT
lesantik [10]

Answer:

HN congruent to NL

Step-by-step explanation:

They have a line crossing both of them, signifiying congruence.

6 0
3 years ago
K is the midpoint of PQ, P has
Pachacha [2.7K]

Answer:

Coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q  (x_2,y_2)

We will use the formula of midpoint: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given midpoint K and x_1,y_1 the coordinates of P we need to find x_2,y_2 the coordinates of Q.

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\

Now, we can write

-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16

So, we get coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

6 0
3 years ago
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