3 years ago

May you help me please?

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

6 0

The answer to this question is C

REY [17]3 years ago

4 0

The answer is C:) because it is on the six, and it goes to the right showing that it includes everything less than 6

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soldier1979 [14.2K]

Corrected Question

Is the function given by:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

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Answer:

(D) Yes, f(x) is continuous at x = 4 because $Lim_{x \to 4}f(x)=f(4)$

Step-by-step explanation:

Given the function:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

A function to be continuous at some value c in its domain if the following condition holds:

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Therefore: $Lim_{x \to 4}f(x)=f(4)=2$

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